thesis1/prep/05Better_knn/q

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2022-10-25 10:45:30 +02:00
The model (mostly) ignores every known sample except one
So there are extensions
$avg=\frac{1}{N} \sum_i knn_i(x)$
$wavg=\frac{1}{N} \sum_i \frac{knn_i(x)}{i}$