correct implementation of the LLB ✨
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@ -14,9 +14,14 @@ import include.TasksHelper as TH
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#The necessary Test for the Liu and Layland Bound
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#The necessary Test for the Liu and Layland Bound
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def test(tasks):
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def test(tasks):
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n = tasks.shape[0]
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U = TH.getTotalUtilization(tasks=tasks, NrTasks=n)
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U_lub = n * ((2 ** (1 / n)) - 1)
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# for fewer tasks than 10, we use the exact computed least upper bound
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if n < 10:
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return U <= U_lub
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#####################
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# from 10 tasks up unlimited, we use the limes of n(2 ** 1/n - 1)
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#YOUR CODE GOES HERE#
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return U <= np.log(2) # round to 0.7 ?
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#####################
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return False
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