successully implemented TDA

schedTests/HyperbolicBound.py

@@ -12,11 +12,15 @@ import include.TasksHelper as TH
 # C_i is accessed as: tasks[i][2]
 # The number of tasks can be accessed as: tasks.shape[0]
 
+
 #The sufficient Test for the Hyperbolic bound
 def test(tasks):
-
+    """ The Hyperbolic bound is given as Π(U + 1) of all tasks: """
-    #####################
+    # compute the hyperbolic bound as product of the U_factor of each task + 1
-    #YOUR CODE GOES HERE#
+    hb = 1
-    #####################
+    for i in range(tasks.shape[0]): # len(tasks) is 10
-
+        hb *= (TH.C_i(tasks, i) / TH.P_i(tasks, i)) + 1
-    return False
+    # compare this computed bound to 2.0
+    # if greater then no guaranty of schedulability
+    # otherwise task set is schedulable
+    return hb <= 2.0

schedTests/LiuAndLaylandBound.py

@@ -14,9 +14,14 @@ import include.TasksHelper as TH
 
 #The necessary Test for the Liu and Layland Bound
 def test(tasks):
+    n = tasks.shape[0]
+    U = TH.getTotalUtilization(tasks=tasks, NrTasks=n)
+    U_lub = n * ((2 ** (1 / n)) - 1)
+    
+    # for fewer tasks than 10, we use the exact computed least upper bound
+   #  if n < 10:
+   #     return U <= U_lub
 
-    #####################
+    # from 10 tasks up unlimited, we use the limes of n(2 ** 1/n - 1)
-    #YOUR CODE GOES HERE#
+    return U <= U_lub # np.log(2) 
-    #####################
 
-    return False

schedTests/TimeDemandAnalysis.py

@@ -13,15 +13,39 @@ import include.TasksHelper as TH
 # C_i is accessed as: tasks[i][2]
 # The number of tasks can be accessed as: tasks.shape[0]
 
-#The Time Demand Analysis Test
+# The Time Demand Analysis Test
+set_num = 0
+
 def test(tasks):
-    #Sorting Taskset by Period/Deadline
+    # Sorting Taskset by Period/Deadline
-    #This makes implementing TDA a lot easier
+    # This makes implementing TDA a lot easier
     shape = tasks.shape
     sortedtasks = tasks[tasks[:, 0].argsort()]
+    
+    # For each tasks in the ordered set
 
-    #####################
+    # calculate the time points for the demand function
-    #YOUR CODE GOES HERE#
+    t_old = 10**-3
-    #####################
+    i = 0
 
-    return False
+    while True:
+        t_new = workload_func(sortedtasks, i, t_old)
+        # if the workload of task i exceeds the deadline
+        if t_new > TH.D_i(sortedtasks, i):
+            return False # task not schedulable
+
+        if t_new == t_old:
+            i += 1
+            t_old = 10**-3
+            #  chech array out of bounds
+            if i == len(sortedtasks):
+                return True
+        t_old = t_new
+    
+
+
+def workload_func(tasks, i, t):
+    sum = 0
+    for k in range(i):
+        sum += math.ceil(t / TH.P_i(tasks, k)) * TH.C_i(tasks, k)
+    return TH.C_i(tasks, i) + sum